有一个SQL语句集合，里面可能有select、select ... left join、update、delete、insert。
要从这语句集合中获取到所有的表名，代码如下:
<?php function get_sql_tables($sqlString) { $sqlString = str_replace( '`','',trim($sqlString) ).' AND 1=1 '; $key = strtolower(substr($sqlString, 0, 6)); if( $key === 'select' ){ $tmp = explode('where' , strtolower( trim( $sqlString ) ) ); $tmp = explode('from',$tmp[0]); if ( strpos($tmp[1],',') !== false && ! stristr( $tmp[1],'select')){ $tmp = explode( ',' , $tmp[1] ); foreach( $tmp as $k => $v ){ $v = trim( $v ); if( strpos( $v , ' ') !== false ){ $tv = explode(' ' , $v); $return[] = $tv[0]; } } return $return; }else{ $expression = '/((SELECT.+?FROM)|(LEFT\s+JOIN|JOIN|LEFT))[\s`]+?(\w+)[\s`]+?/is'; } }else if( $key === 'delete' ){ $expression = '/DELETE\s+?FROM[\s`]+?(\w+)[\s`]+?/is'; }else if( $key === 'insert' ){ $expression = '/INSERT\s+?INTO[\s`]+?(\w+)[\s`]+?/is'; }else if( $key === 'update' ){ $tmp = explode( 'set' , strtolower( str_replace('`','',trim( $sqlString ) ) ) ); $tmp = explode( 'update' , $tmp[0] ); if ( strpos($tmp[1] , ',' ) !== false && ! stristr( $tmp[1] , 'update' ) ){ $tmp = explode( ',' , $tmp[1] ); foreach( $tmp as $k => $v ){ $v = trim( $v ); if( strpos( $v , ' ') !== false ){ $tv = explode(' ' , $v); $return[] = $tv[0]; } } return $return; }else{ $expression = '/UPDATE[\s`]+?(\w+)[\s`]+?/is'; } } preg_match_all($expression, $sqlString, $matches); return array_unique(array_pop($matches)); }使用姿势：
<?php $sql = "select count(*) as count from order as a left join user as b on a.user_id = b.user_id where a.title like '%老季%'"; var_dump(get_sql_tables());#输出结果：order和user $sql = "select * from T_5 a, T_6 b , T_7 c where a.id=b.id"; var_dump(get_sql_tables());#输出结果：Array ( [0] => T_5 [1] => T_6 [2] => T_7 )
